Tolong bantu no. 2 nya

PR = 12 cm
PS = (PQ ÷ 2) = (12 cm ÷ 2) = 6 cm

[tex]RS= \sqrt{PR^2-PS^2} \\ \\ RS = \sqrt{12^2-6^2} \\ \\ RS= \sqrt{144-36} \\ \\ RS= \sqrt{108}= \sqrt{36 \times 3}= \sqrt{36} \times \sqrt{3} \\ \\ RS=6 \sqrt{3} [/tex]

Jawaban (D)

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