tolong kasih tau dengab carabga ya,,, terimakasih:)

Pertama, rangkaian paralel harus diserikan terlevih dahulu.
[tex] \frac{1}{rp} = \frac{1}{2} + \frac{1}{6} \\ \frac{1}{rp} = \frac{3}{6} + \frac{1}{6} \\ \frac{1}{rp} = \frac{4}{6} = \frac{2}{3} \\ rp = \frac{3}{2} = 0.5 \: ohm \\ r \: total = 1.5 \: ohm + 0.5 \: ohm = 2 \: ohm \\ [/tex]
I total / kuat arus total
[tex] = \frac{v}{r} = \frac{6 \: v}{2 \: ohm} = 3.00 \: a[/tex]