tolong pame cara yg (b) terimakasih!

Soal a.

[tex]=(3^{-2}\times \frac{3}{5})^2 \\ \\ =((3^{-2})^2)\times((\frac{3}{5})^2) \\ \\ =(3^{(-2\times2)})\times( \frac{3^2}{5^2}) \\ \\= 3^{-4}\times \frac{3^2}{5^2} \\ \\=\frac{3^{(-4+2)}}{5^2} \\ \\ = \frac{3^{-2}}{5^2} \\ \\ =\frac{1}{3^2\times5^2}........\text{Rumus :}\ a^n\times b^n=(ab)^n \\ \\ = \frac{1}{15^2} \\ \\ = \frac{1}{225} = 0,0044[/tex]

Soal b.

[tex]=(-2+3)^3\times (5-3)^{(3+1)}\times (3-1)^{(3+2)} \\ \\ =(1)^3\times (2)^4\times (2)^5 \\ \\ =1\times 2^{(4+5)} \\ \\ =2^9 \\ \\ =512[/tex]

***Semoga Terbantu***