Nilai r adalah? - Phytagoras

[tex] {20}^{2} = {12}^{2} + {x }^{2} \\ 400 = 144 + {x}^{2} \\ {x}^{2} = 400 - 144 \\ {x}^{2} = 256 \\ x = \sqrt{256} = 16[/tex]
[tex] {13}^{2} = {12}^{2} + {y}^{2} \\ 169 = 144 + {y}^{2} \\ {y}^{2} = 169 - 144 \\ {y}^{2} = 25 \\ y = \sqrt{25 } = 5 \\ [/tex]
[tex]y + r = x \\ 5 + r = 16 \\ r = 16 - 5 \\ r = 11[/tex]

Rumus nya b²=a²-c² jdi
b²=20²-13²
b²=400-169
b²=231
b²=akar 231
Tinggal cari akar dari 231

Semoga membantu :)