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[tex] \sqrt{16} + \sqrt[3]{27} - \sqrt{25 } \\ = 4 + {3}^{ \frac{3}{3} } - 5 = 4 + 3 - 5 = 2 \\ [/tex]

[tex] \sqrt[3]{125} + \sqrt[4]{ \frac{1}{81} } + \sqrt[5]{32} \\ = {5}^{ \frac{3}{3} } + {3}^{ \frac{ - 4}{4} } + {2}^{ \frac{5}{5} } \\ = 5 + {3 }^{ - 1} + 2 \\ = 7 + \frac{1}{3} = \frac{21 + 1}{3} = \frac{22}{3} = 7 \frac{1}{3} [/tex]