Matematika

Pertanyaan

cari fpb dan kpk dari
a.252 dan 378
b.16, 56 dan 72
c.64, 80 dan 96
d.64 dan 220

2 Jawaban

  • jawabannya
    a. 252= 2²×3²×7
    378= 2×3³×7
    fpb= 2×3²×7= 126
    kpk= 2²×3³×7= 756

    b. 16= 2⁴
    56= 2³×7
    72= 2³×3²
    fpb= 2³= 8
    kpk= 2⁴×3²×7= 1.008

    c. 64= 2 pangkat 6
    80= 2⁴×5
    96= 2 pangkat 5 × 5
    fpb= 2⁴= 16
    kpk= 2 pangkat 6 × 3×5 = 960

    d. 64= 2 pangkat 6
    220= 2²×5×11
    fpb= 2²= 4
    kpk= 2 pangkat 6 ×5×11 = 3.520


    #SEMOGA MEMBANTU
  • a)252 = 2 x 2 x 3 x 3 x 7
    378 = 2 x 3 x 3 x 3 x 7
    fpb =2 x 3 x 3 x 7 = 126
    kpk = 2 x 2 x 3 x 3 x 3 x 7 = 756
    b)16 = 2 x 2 x 2 x 2
    56 = 2 x 2 x 2 x 7
    72 = 2 x 2 x 2 x 3 x 3
    fpb = 2 x 2 x 2 = 8
    kpk = 2 x 2 x 2 x 2 x 3 x 7 = 336
    c)64 = 2 x 2 x 2 x 2 x 2 x 2
    80 = 2 x 2 x 2 x 2 x 5
    96 = 2 x 2 x 2 x 2 x 2 x 3
    fpb = 2 x 2 x 2 x 2 = 16
    kpk = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 5 = 980
    d)64 = 2 x 2 x 2 x 2 x 2 x 2
    220 = 2 x 2 x 5 x 11
    fpb = 2 x 2 = 4
    kpk = 2 x 2 x 2 x 2 x 2 x 2 x 5 x 11 = 3520

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