1). 2√27+6√12-2√48= Tolong di bantu kak

[tex]2 \sqrt{9 \times 3} + 6 \sqrt{4 \times 3} - 2 \sqrt{16 \times 3} \\ \\ = 2 \times 3 \sqrt{3} + 6 \times 2 \sqrt{3} - 2 \times 4 \sqrt{3} \\ \\ = 6 \sqrt{3} + 12 \sqrt{3} - 8 \sqrt{3} \\ \\ = 18 \sqrt{3} - 8 \sqrt{3 } \\ \\ = 10 \sqrt{3} [/tex]
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