Matematika

Pertanyaan

f(x)=x-2,g(x)=x^2,h(x)=2x+1, tentukan (hogof)(2)=

1 Jawaban

  • (h○g○f)(2) ....??

    cari dulu (g○f)(x)

    f(x) = x - 2
    g(x) = x^2
    h(x) = 2x + 1

    (g○f)(x) = (x-2)^2
    = (x-2)(x-2)
    = x^2 - 4x + 4

    ,,,

    (h○g○f)(x)
    = 2 (x^2 - 4x + 4) + 1
    = 2x^2 - 8x + 8 + 1
    = 2x^2 - 8x + 9

    maka
    (h○g○f)(2)
    = 2(2)^2 - 8(2) + 9
    = 8 - 16 + 9
    = -8 + 9
    = 1 <<==== finish

Pertanyaan Lainnya