Tolong jawab pertanyaan ini yyyy plis....................

Luas Segitiga Sama Sisi

[tex]L= \frac{1}{4}\times(s^2)\times \sqrt{3}\\ \\Sisi= \frac{2}{2 \sqrt{2}-1 }\\ \\ \\L= (\frac{1}{4})\times(\frac{2}{2 \sqrt{2}-1})^2\times (\sqrt{3})\\ \\L= (\frac{1}{4})\times(\frac{2^2}{(2 \sqrt{2}-1 )^2})\times (\sqrt{3})\\ \\L=(\frac{1}{4})\times(\frac{4}{((2^2\times2)-2(2 \sqrt{2})+1^2 )})\times (\sqrt{3})\\ \\L= (\frac{1}{4})\times(\frac{4}{(8-4 \sqrt{2}+1 )})\times (\sqrt{3})\\ \\L= (\frac{1}{9-4 \sqrt{2} })\times (\sqrt{3})\\ \\L= \frac{\sqrt{3}}{(9-4 \sqrt{2})}[/tex]

[tex]L= \frac{\sqrt{3}}{9-4 \sqrt{2}}\times \frac{9+4 \sqrt{2}}{9+4 \sqrt{2}} \\ \\ L=\frac{\sqrt{3}(9+4 \sqrt{2})}{9^2-(4 \sqrt{2})^2} \\ \\ L= \frac{9 \sqrt{3}+4 \sqrt{6} }{81-(16\times2)}\\ \\L= \frac{9 \sqrt{3}+4 \sqrt{6} }{81-32}\\ \\ L= \frac{9 \sqrt{3}+4 \sqrt{6}}{49} [/tex]

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