tolong jawab ya kakak kakak plis besok di cocokin nih.....

[tex]\sqrt{m}+ \frac{1}{\sqrt{m} }= \sqrt{7}.......\text{kedua ruas dikuadratkan} \\ \\(\sqrt{m}+ \frac{1}{\sqrt{m} })^2= (\sqrt{7})^2 \\ \\ ( \sqrt{m})^2+(2\times \sqrt{m}\times \frac{1}{\sqrt{m} })+(\frac{1}{(\sqrt{m}) })^2=7 \\ \\m+2+\frac{1}{m}=7 \\ \\ m+\frac{1}{m}=7-2 \\ \\ m+\frac{1}{m}=5 [/tex]

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