Diketahui segitiga ABC, siku-siku di C, AC=5cm, AB=13cm. Sudut BAC=alpha dan sudut ABC=beta. Tentukan nilai-nilai perbandingan trigonometri

jawab

ΔABC siku siku di C

AC = 5
AB = 13
BC = √(AB² - AC²) = 12

<BAC = α, <ABC = β

sin α = 12/13
cos α = 5/13
tan α = 12/5
cosec α = 13/12
sec α =  13/5
cot α = 5/12

sin β = 5/13 
cos β = 12/13
tan β = 5/12
cose β = 13/5
sec β = 13/12
cot β = 12/5