Matematika

Pertanyaan

dengan metode substitusi 5x+2y=1/2 dan -3x+2y=1/2

1 Jawaban

  • 5x+2y=1/2
    -3x+2y=1/2

    2y = 1/2 - 5x

    -3x+2y=1/2
    -3x+(1/2 - 5x)=1/2
    -8x + 1/2 = 1/2
    -8x = 1/2-1/2
    -8x = 0
    x = 0

    5x+2y=1/2

    -3x+2y=1/2 (bagi -3)
    x-2/3y=-1/6
    x = 2/3y - 1/6

    5(2/3y - 1/6) + 2y = 1/2
    10/3y - 5/6 + 2y = 1/2
    10/3y - 5/6 + 6/3y = 1/2
    16/3y - 5/6 = 1/2
    16/3y = 1/2 + 5/6 (kali 3/16)
    y = 3/32 + 15/96
    y = 9/96 + 15/96
    y = 24/96
    y = 1/4

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