tolong jawab ya.....makasih....

[tex]\frac{2^3}{125^{\frac{2}{3}}-\left ( \frac{1}{3} \right )^{-2}} \\ =\frac{2^3}{125^{\frac{2}{3}}-\left (3^{-1} \right )^{-2}} \\ = \frac{2^3}{125^{\frac{2}{3}}-3^2} \\ = \frac{2^3}{\left (5^3 \right )^{\frac{2}{3}}-3^2} \\ = \frac{2^3}{5^2-3^2} \\ = \frac{2^3}{25 - 9} \\ = \frac{2^3}{16} \\ = \frac{2^3}{2^4} \\ = 2^{3-4}\\ = 2^{-1} \\ = \frac{1}{2}[/tex]