Integral 2 sampai 5 (x^3-7x^2+10x)dx

[tex]in \binom{2}{5} ( {x}^{3} - 7 {x}^{2} + 10x)dx \\ = \frac{3}{4} {x}^{4} - \frac{7}{3} {x}^{3} + 5 {x}^{2} \binom{5}{2} \\ = ( \frac{3}{4} \times {5}^{4} - \frac{7}{3} \times {5}^{3} + 5 \times {5}^{2} ) - ( \frac{3}{4} \times {2}^{4} - \frac{7}{3} \times {2}^{3} + 5 \times {2}^{2} ) \\ = (\frac{1875}{4} - \frac{875}{3} + 125) - ( \frac{48}{4} - \frac{56}{3} + 20) \\ = \frac{1827}{4} - \frac{819}{3} + 105 \\ = \frac{5481 - 3276 + 1260}{12} \\ = \frac{3465}{12} = \frac{1155}{4} [/tex]