Matematika

Pertanyaan

jika f(x)= 3x+2 dan g(x)= -x ,tentukan
a.fog.
b.gof
c.fof
d.gog

2 Jawaban

  • fog= f(g(x))= 3(g(x)+2
                      = 3(-x)+2= -3x+2

    gof= g(f(x))= -(f(x))
                      = -(3x+2)=-3x-2

    fof= f(f(x))= 3(f(x))+2
                    = 3(3x+2)+2 = 9x+6+2 = 9x+8

    gog=g(g(x))= -(g(x))
                       = -(-x)= x
  • a)
    (f○g)(x)
    = f(g(x))
    = f(-x)
    = 3(-x) + 2
    = - 3x + 2

    b)
    (g○f)(x)
    = g(f(x))
    = g(3x + 2)
    = - (3x + 2)
    = - 3x - 2

    c)
    (f○f)(x)
    = f(f(x))
    = f(3x + 2)
    = 3(3x + 2) + 2
    = 9x + 6 + 2
    = 9x + 8

    d)
    (g○g)(x)
    = g(g(x))
    = g(- x)
    = - (- x)
    = x

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