carilah akar-akar persamaan kuadrat 1. X²+3x+-10=0 2. 3X²-13x+12=0 3. X²+6x+9=0

1)
x²+3x-10 = 0
(x-2)(x+5) = 0
x-2 = 0
x = 2
atau
x+5 = 0
x = -5


2)
3x²-13x+12 = 0
(3x-4)(x-3) = 0
3x-4 = 0
3x = 4
x = 4/3
x = 1 1/3
atau
x-3 = 0
x = 3


3)
x²+6x+9 = 0
(x+3)(x+3) = 0
x+3 = 0
x = -3