hitunglah luas daerah yang dibatasi opeh kurva y=X²-5x dan sumbu x diantara x=-2 dan x=5

Batas IntegraL
x² - 5x = 0
x(x - 5) = 0
x = 0 ; x = 5

Luas
= ∫(x² - 5x) dx [0_-2] - ∫(x² - 5x) dx [5_0]
= (1/3 x³ - 5/2 x²) [0_-2] - (1/3 x³ - 5/2 x²) [5_0]
= 0 - ((-2)³/3 - 5/2 . (-2)²) - (5³/3 - 5/2 . 5² - 0)
= -(-8/3 - 10) - (125/3 - 125/2)
= 38/3 + 125/6
= (76 + 125)/6
= 201/6
= 33,5 satuan luas