tolong jawab ya no 1

[tex]1) \: \sqrt[4]{ {25}^{8} } = {25}^{ \frac{8}{4} } = { ({5}^{2}) }^{2} = {5}^{4}[/tex]

[tex]\text{a.}\ \sqrt[4]{25^8}=(25^8)^ \frac{1}{4}=(5^2)^ {(8\times\frac{1}{4})} =5^{(2\times8\times\frac{1}{4})}=5^{(\frac{2\times8}{4})}=5^4=625 \\ \\\text{b.}\ \sqrt[5]{32^8}=(32^8)^ \frac{1}{5}=(2^5)^ {(8\times\frac{1}{5})} =2^{(5\times8\times\frac{1}{5})}=2^{(\frac{5\times8}{5})}=2^8=256 \\ \\\text{c.}\ \sqrt[3]{125^2}=(125^2)^ \frac{1}{3}=(5^3)^ {(2\times\frac{1}{3})} =5^{(3\times2\times\frac{1}{3})}=5^{(\frac{3\times2}{3})}=5^2=25[/tex]

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