tlong doang isi ini sekalian jalan nya

[tex]\text{No. 1)}\ \ ( \frac{3}{8})^4=( \frac{3}{2^3} )^4= \frac{3^4}{2^{3\times4}}= \frac{3^4}{2^{12}}= 3^4.2^{-12}\\ \\\text{No. 2)}\ \ ( \frac{-1}{3})^{-3}= \frac{(-1)^{-3}}{3^{-3}}= \frac{3^3}{(-1)^3}= \frac{3^3}{(-1)}=-(3^3)\\ \\\text{No. 3)}\ \ ( \frac{1}{2})^{3}\div ( \frac{1}{2})^4 = (\frac{1}{2})^{(3-4)}= (\frac{1}{2})^{-1}= \frac{(1)^{-1}}{2^{-1}}= \frac{2^1}{1^1}=2^1=2[/tex]

[tex]\text{No. 4)}\ \ ( \frac{5}{x})^{6}\div ( \frac{5}{x})^{2} = (\frac{5}{x})^{(6-2)}= (\frac{5}{x})^{4}= \frac{5^{4}}{x^{4}}=5^4.x^{-4} \\ \\\text{No. 5)}\ \ (( \frac{-4}{7})^{-2})^{3}=( \frac{-4}{7})^{(-2\times3)}=( \frac{-4}{7})^{-6}=\frac{(-4)^{(-6)}}{7^{(-6)}}=\frac{7^{6}}{(-4)^{6}} \\ \\ \text{No. 6)}\ \ ( \frac{2}{3} + \frac{4}{5})^{-1}=( \frac{10}{15} + \frac{12}{15})^{-1}=( \frac{22}{15})^{-1} =( \frac{22^{-1}}{15^{-1}})= \frac{15}{22}=0,68 [/tex]

[tex]\text{No. 7)}\ \ ( \frac{2}{5})^{(-4)} \times( \frac{2}{5})^{(3)}=( \frac{2}{5})^{(-4+3)}=( \frac{2}{5})^{(-1)}=( \frac{2^{(-1)}}{5^{(-1)}}) \\ \\ =( \frac{5^{1}}{2^{1}})= \frac{5}{2}=2,5 \\ \\\text{No. 8)}\ \ (\frac{3}{4})^{(-3)} \div( \frac{3}{4})^{(2)}=( \frac{3}{4})^{(-3-2)}=( \frac{3}{4})^{(-5)}=( \frac{3^{(-5)}}{4^{(-5)}}) \\ \\ =( \frac{4^{5}}{3^{5}})= \frac{1.024}{243}=4,21[/tex]

***Semoga Terbantu***