(2√2-√5)²= bab:pemangkatan dari akar suatu bilangan

semoga bermanfaat Folow kakak ya

(a - b)² = a² - 2ab + b²

[tex]=(2 \sqrt{2}- \sqrt{5})^2 \\ \\ =(2 \sqrt{2})^2-(2\times2 \sqrt{2}\times \sqrt{5})+( \sqrt{5})^2 \\ \\ =(2^2\times( \sqrt{2})^2)-(4 \sqrt{10})+(5) \\ \\ =(4\times2)-(4 \sqrt{10})+(5) \\ \\ =8-(4 \sqrt{10})+(5) \\ \\ =13-4 \sqrt{10} [/tex]

***Semoga Terbantu***