Tolong jawab no 5 sampai 8 pakai cara

5. 
[tex] \frac{9x^{2}y^{3}}{2ab} : \frac{3x^{2}y}{2a^{2}b} \\ = \frac{9x^{2}y^{3}}{2ab} . \frac{2a^{2}b}{3x^{2}y} \\ = \frac{3y^{2}}1} . \frac{a}{1} \\ =3ay^{2}[/tex]

8.
[tex] \frac{3}{2x-5} + \frac{4}{3x+1} \\ = \frac{3(3x+1)}{(2x-5)(3x+1)} + \frac{4(2x-5)}{(2x-5)(3x+1)} \\ = \frac{9x+3}{6x^{2}-13x-5} + \frac{8x-20}{6x^{2}-13x-5} \\ = \frac{9x+3+8x-20}{6x^{2}-13x-5} \\ = \frac{17x-17}{6x^{2}-13x-5} \\ = \frac{17(x-1)}{6x^{2}-13x-5}[/tex]