tolong bantu dong jawaban nya apa tolong dijabarkan

Ans:
1\\
[tex]\left(\begin{array}{ccc}a-4&-8&2d-3\\b&2c&-13\end{array}\right) = \left(\begin{array}{ccc}2a&-8&11\\2b-5&3c+8&-13\end{array}\right) \\\\ \begin{array}{rcl}a-4&=&2a\\-4&=&a\\a&=&\bf-4 \end{array}\\\\\\ \begin{array}{rcl}b&=&2b-5\\-b&=&-5\\b&=&5\end{array}\\\\\\ \begin{array}{rcl}2c&=&3c+8\\-c&=&8\\c&=&-8 \end{array}\\\\\\\ \begin{array}{rcl}2d-3&=&11\\2d&=&8\\d&=&\frac{8}{2}\\d&=&4 \end{array}[/tex]

2\\
[tex]\left(\begin{array}{ccc}4x-2y&-4\\5x-y&-3\end{array}\right) = \left(\begin{array}{ccc}-16&-4\\4&-3\end{array}\right)\\\\ \begin{array}{rcl}4x-2y&=&-16\\4x&=&-16+2y\\x&=&-4+\frac{1}2y\end{array}\\\\\\ \begin{array}{rcl}5x-y&=&4\\-y&=&4-5x\\y&=&-4+5x\dots(\text{ii})\end{array}\\\\\\ \text{substitusikan}\;\;x=-4+\frac{1}2y\;\;\text{ke persamaan kedua};\\\\ y=-4+5\big(-4+\frac{1}2y\big)\\\\ y=-4-20+\frac{5}2y\\\\ -\frac{3}2y=-24\\\\ .\;\;\;\;\;y=\frac{-24}{-\frac{3}{2}}\\\\ .\;\;\;\;\;y=16\\\\[/tex]

[tex]\text{substitusikan}\;\;y=16\;\;\text{ke persamaan}\;\;4x-2y=-16;\\\\ \begin{array}{rcl}4x-2y&=&-16\\4x-2\cdot(16)&=&-16\\4x-32&=&-16\\4x&=&16\\x&=&4 \end{array}[/tex]