SPLDV metode substitusi dari x+2y = 5 dan 4y-3x=0

jawab

x+ 2y = 5
x = 5 - 2y  sub ke 4y - 3x = 0
4y - 3(5 - 2y)= 0
4y - 15 + 6y = 0
10y = 15
y = 15/10
y = 3/2

x = 5 - 2y
x = 5- 2(3/2)
x = 5 - 3
x = 2
(x,y)=(2,  3/2)