SPLDV sistem substitusi dari x+2y=5 dan 4y-3x=0

x+2y=5
x=5-2y

4y-3x=0
4y-3(5-2y)=0
4y-15+6y=0
10y=15
y=3/2

x=5-2y=5-2(3/2)=5-3=2

Persamaan (1)

x + 2y = 5
x = -2y + 5

Substitusi (2)

4y - 3x = 0
4y - 3(2y + 5) = 0
4y + 6y - 15 = 0
10y = 15
y = 15/10
y = 3/2

Substitusi (1)

x + 2y = 5
x + 2(3/2) = 5
x + 3 = 5
x = 5 - 3
x = 2

HP = {(x, y) = (2, 3/2)}

Semoga membantu :)