diketahui f(x)=ax+b. jika f(-2)=-19 dan f(3)=16, maka nilai f(1)=...

Materi : SPLDV
Kelas : IX

f(x) = ax + b = c
f(-2) = - 19
f(3) = 16

f(x) = ax + b = c
f(-2) = a(-2) + b = -19
= -2a + b = -19 ... Pers 1

f(x) = ax + b = c
f(3) = a(3) + b = 16
= 3a + b = 16 .... Pers 2


#Eliminasi pers 1 dan 2 :
-2a + b = -19
3a + b = 16
__________ --
-5a + 0 = -35
a = -35 / -5
a = 7

#Subsitusi a = 7 ke pers 1
-2a + b = -19
-2(7) + b = -19
-14 + b = -19
b = -19 + 14
b = -5

didapat nilai baru adalah :
f(x) = ax + b
f(x) = 7x + -5
f(1) = 7(-1) + -5
= -7 + -5
= -12 → Adalah jawbannya


Semoga Membantu...